We want to factor the following expression: 81x^6– (y+1)^2
We can factor the expression as (U +V)(U-V) where U and V are either constant integers or single-
variable expressions.
1) What are U and V?

We have

Step-by-step explanation:

We want to factor the expression in the form of (U+V)(U-V)

We need to find U and V

We can use formula :

We can write as

Now we have the expression:

Applying formula:

So, we have

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?