What is an equation of the line that passes through the point (2,-5) and is parallel to the line 6x +y = 6?

y = -6x + 7

Step-by-step explanation:

In this question, we need to find the equation of a line with the given information.

We know that the line passes through (2, -5).

We also know that the line is parallel to the line 6x + y = 6, which means that it has to have the same slope.

To make it simpler to understand, we can change the equation into slope format:

y = -6x + 6

This means that our new line should have a slope of -6.

With the information above, we can plug in our new values to get the y-intercept of our equations, since we don't have that information.

Plug in your slope and coordinates to the y = mx + b equation and solve for b:

-5 = -6(2) + b

-5 = -12 + b

Add 12 to both sides.

7 = b

Our y-intercept would be b.

Now, we can plug in all our information to get our new equation:

y = -6x + 7

Your answer would be y = -6x + 7

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: