WILL GIVE BRAINLIEST!! Ignore the $

Meyer rolls two fair, ordinary dice with the numbers $1,2,3,4,5,6$ on their sides. What is the probability that at least one of the dice shows a square number?

Two numbers on each die are squares: 1 and 4. 4 numbers on each die are not squares: 2 , 3, 5, and 6. there are 16 ways for him to roll a non-square die, out of 36 outcomes for the pair of dice. The other 20 options each have a square number showing on one or both dice. So, the probability is 5/9. hope this helps please pick my answer as brainliest, have a good day!

the answer is 40.

proof: