Jane, andre, and maria pick apples. andre picks three times as many pounds as maria. jane picks two times as many pounds as andre. the total weight of the apples is 840 pounds. how many pounds of apples does andre pick?

So for Andre draw three boxes, for Marie draw one box, and for Jane draw 2 boxes. You say 840 divided by 6 cause its six boxes in total. When you get your answer write it all the boxes. After add up all the boxes for Andre and that's your answer.

Jane = j
Andre = a
Maria = m

Andre picks 3 times as many pounds as Maria
3m

Jane picks two times as many pounds as Andre
2a

So:
j = 2a
a = 3m
m = 1m

The total weight is 840 pounds.
So: 2a + 3m + 1m = 840
Since a = 3m, replace the a in 2a with 3m : 2(3m)
2(3m) + 3m + 1m = 840
2(3m) = 6m [multiply 2 with 3]
6m + 3m + 1m = 840
Add all together
10m = 840
Divide 10 by both sides
m = 84
Since Maria picked 84 pounds and Andre picked 3 times the amount Maria picked, multiply 84 by 3 to get the final result.

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)