PLEASE HELP!
m∥n m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC What is m∠3 ?

m∠3 = 49°

Step-by-step explanation:

From the picture attached,

lines m and n are the parallel lines and line t is a transversal line intersecting these parallel lines at E and B respectively.

Therefore, ∠DEF ≅ ∠ABC [Exterior alternate angles]

m∠1 + m∠2 = m∠4 + m∠5

m∠4 = m∠5 [line s bisects ∠ABC]

50° + 48° = m∠4 + m∠4

98° = 2m∠4

m∠4 = 49°

Since, ∠4 ≅ ∠3 [Vertically opposite angles]

m∠3 = 49°

true? is that what you're asking or do you mean something else?

answer: b.48 for

step-by-step explanation: