At the shorter waterfall, water falls uninterrupted for 1552 feet before entering the river below. The height h above the river in feet of water going over the edge of the waterfall is modeled by h\left(t\right)=-16t^2+1552h(t)=−16 t^2+1552, where is the time in seconds after the initial fall. Estimate the time it takes for the water to reach the river. Round your answer to the nearest tenth.

Step-by-step explanation:

First note that the river is on the ground level. The height of the river at the ground level is 0

Given the the height h above the river in feet of water going over the edge of the waterfall is modeled by h(t)=-16t^2+1552

When h = 0

0 = -16t^2+1552

16t^2 = 1552

t² = 1552/16

t² = 97

t = √97

t = 9.9secs

Hence the time it takes is 9.9secs to the nearest tenth

i'm sorry i don't know

step-by-step explanation:

something over 10 so ? /10

step-by-step explanation: