The Aluminum Association reports that the average American uses 56.8 pounds of aluminum in a year. A random sample of 51 households is monitored for one year to determine aluminum usage. If the population standard deviation of annual usage is 12.3 pounds, what is the probability that the sample mean will be more than 59 pounds . a) 0.1003
b) 0.3997
c) 0.6003
d) 0.8997
e) 0.0003

A: 0.1003

Step-by-step explanation:

We are given;

Population mean; μ = 56.8

Population size; n = 51

Population standard deviation; σ = 12.3

We want to find; P(x > 59)

We will use the z-score formula.

z = (x - μ)/(σ/√n)

z = (59 - 56.8)/(12.3/√51)

z = 1.28

From z-distribution table attached, we have; P(z < 1.28) = 0.8997

Thus;

P(z > 1.28) = 1 - 0.8997 = 0.1003

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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answer: check all that apply, where the options?

step-by-step explanation: