IF THE RATIO IN A VALENTINE'S DAY CANDY BOX OF MILK TO DARK
CHOCOLATES IS 23. HOW MANY
DARK CHOCOLATES ARE THERE IF
THERE ARE 8 MILK CHOCOLATES?

12 dark chocolates

Step-by-step explanation:

Let there are 2x milk chocolates and 3x dark chocolates.

Total no of milk chocolates = 8

ATQ,

2x = 8

x = 4

Dark chocolates = 3x

= 3(4)

= 12

Hence, there are 12 dark chocolates.

c

step-by-step explanation:

at least i think its

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752