Use the drawing tool(s) to form the correct answer on the provided graph. Graph the solution to this system of inequalities in the coordinate plane.

3y>2x=+12
2x+y≤-5

We have the system:

3y>2x+12

2x+y≤-5

The first step will be to write the inequalities as lines:

y  > (2x + 12)/3

y ≤ -5  - 2 x

Now that the equations are written in slope-intercept form, we just need to draw the lines.

In the first case, we have the symbol ">", which means that the line will be a dashed line, and the shaded area will be above that line.

In the second equation we have the symbol "≤", this means that the line will be a solid line, and the shaded area will be below that line.

The graph of both inequalities is shown below. Where the solution to the system is the double shaded area.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.