Thomas and Freya have ages that are consecutive integers. The sum of their ages is 16 less than three times the larger of the two ages. Which equation could be used to solve for the smaller age, a? 1. a+(a +1) = 3(a+1) - 16
2. a + (a+2) = (3a + 1) - 16
3. a(a + 1) = 16 - 3a
4. a(a + 2) = 16 - 3(a +2)

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

step-by-step explanation:

im guessing (23,14). hope this : )

33/100 is what i got