If f(x) = 8x + 1 and the graph of g is the graph f translated 2 units to right, which equation represents g? A. g(x) = (6x + 1) + 2
B. g(x) = 8(x + 2) + 1
C. g(x) = (6x+1) - 2
D. g(x) = 8(x - 2) + 1

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The vertex of this parabola is at (-2,-3). when the x-value is -1, the y-value is -5. what is the coefficient of the squared expression in the parabola's equation?

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.