X^4-13x^2+12=0 solve for x

Let

x = ± 1, x = ± 2

Step-by-step explanation:

Given

- 13x² + 12 = 0

Use the substitution u = x² , then

u² - 13u + 12 = 0 ← in standard form

(u - 1)(u - 12) = 0 ← in factored form

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

u - 12 = 0 ⇒ u = 12

Now substitute x² = u back, that is

x² = 1 ( take the square root of both sides )

x = ± = ± 1

x² = 12 , then

x = ± = ± = ± 2

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