What is an equation of the line that passes through the points (−2,8) and (1,−1)

y = -3x + 2

Explanation:

Do the rise over run equation to find slope

Slope = 3

Plug in slope to equation and also choose one of the coordinate points to plug in x and y so you can find b

Plug in all of this to get final y=mx+b form

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

ian gonna lie that is way to much