Otto spent 3/4 of the money he had saved on a new video game. if the video game cost $48, how much money did he have before he bought the game?

$64

Step-by-step explanation:

Given: The part of money he spent =3/4

Let the total money Otto has be 'x'.

Then according to the question, we have

Multiply 4 on both the sides, we get

Divide 3 on both the sides, we get

Hence, the money he had  before he bought the game = $64

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.