Solve the system of linear equations by elimination.

x+4y=1
3x+5y=10

x = 5 , y = -1

Step-by-step explanation:

Solve the following system:

{4 y + x = 1 | (equation 1)

5 y + 3 x = 10 | (equation 2)

Swap equation 1 with equation 2:

{3 x + 5 y = 10 | (equation 1)

x + 4 y = 1 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{3 x + 5 y = 10 | (equation 1)

0 x+(7 y)/3 = -7/3 | (equation 2)

Multiply equation 2 by 3/7:

{3 x + 5 y = 10 | (equation 1)

0 x+y = -1 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{3 x+0 y = 15 | (equation 1)

0 x+y = -1 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 5 | (equation 1)

0 x+y = -1 | (equation 2)

Collect results:

{x = 5 , y = -1

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

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step-by-step explanation: