Let 3z=(2w-5)^3. If dw/dt =1/3, find dz/dt when z=9

3z = (2w - 5)³

When z = 9, we have

27 = (2w - 5)³   →   3 = 2w - 5   →   w = 4

Differentiate both sides with respect to t :

3 dz/dt = 3 (2w - 5)² dw/dt

dz/dt = (2w - 5)² dw/dt

Plug in everything you know and solve for dz/dt :

dz/dt = 3² • (1/3)

dz/dt = 3

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"