Solve 1/2cot(x)≥1/2 over 0≤x≤2pi Solving a Trigonometric Inequality











The answer is B.
The second one.
0<x≤pi/4 and pi≤x≤5pi/4

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

no its the same as every other grade

step-by-step explanation:

y-y1=m(x-x1)

y-1=1(x-8)