Asatellite view of a hurricane is placed on a coordinate plane. the outside edges of the hurricane are located at (4, 6) and (11, 6). solve for the width and the center of the hurricane.

a. width = 4 center = (7.5, 6)
b. width = 4 center = (8, 6)
c. width = 19 center = (5, 8.5)
d. width = 7 center = (7.5, 6)

1st point (4,6)
2nd point (11,6)

Let us use the distance formula to get the width and center.

distance = √(x2-x1)² + (y2-y1)²
d = √(11-4)² + (6-6)²
d = √7² + 0²
d = √7²
d = 7  this is the width .

Answer is D. width = 7 ; center = (7.5,6)

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