In triangle def measurement angle d = 45 degrees meausrement angle e = 63 degrees and ef = 24 inches. what is de to the nearest tenth of a inch?

DE = 32.8 inches is the answer.

Step-by-step explanation:

It is given that In the given triangle DEF, angle D = 45°, ∠E = 63° and EF = 24 inches.

We have to calculate the length of DE.

From the sine rule of a triangle

As we know sum of all angles of a triangle is 180°

Therefore ∠D + ∠E + ∠F = 180°

45 + 63 + F = 180

F = 180-108 = 72°

Now from the sine rule written above

.029 = .95/DE

DE = 0.95/0.029 = 32.75 ≈ 32.80 inches

Answer will be DE = 32.80 inches

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

alright so i think for this one it would to draw it out. this may be hard for me to try and draw, but i will do my best on here:

        r

  /       |     \

notice how it forms 2 triangles inside one bigger triangle.

so if we know the angle spr is the same as psr that is saying the measure of angle p is the same as angle s. this means the big triangle psr is either isosceles or equilateral. in both cases, the triangle is perfectly symmetrical when split down the middle, which is in this case rq. because we know it is perfectly symmetrical on both sides, we know that the two triangles inside the bigger one are equal.