A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, . y=-16x^2+261x+130

Step-by-step explanation:

Given the maximum height of the rocket modelled by the expression

y=-16x^2+261x+130

The rocket velocity at its maximum height is zero.

v(x) = dy/dx = 0

dy/dx = -32x + 261

0 = -32x + 261

32x = 261

x = 261/32

x= 8.156secs

Substitute the time into the given expression'

y=-16(8.16)^2+261(8.16)+130

y = -1,064.88 + 2,129.76 + 130

y = 1194.88

3x3 = 9 and 2x2 = 4

step-by-step explanation: