Find a basis for the orthogonal complement of the subspace of R4 spanned by the vectors. v1 = (1, 4, -5, 3), v2 = (4, 15, 0, 5), v3 = (1, 3, 15, -4) The basis for the row space is

W1 = ( ... , ... , 1, 0)
W2= (..., ..., 0, 1)

W1 =  ( -75, 20, 1 , 0 )

W2 = ( 25, -7 , 0, 1 )

Step-by-step explanation:

attached  below is the remaining part of the solution

for a homogenous system of equation ; Ax = 0

x1 + 4x2 -5x3 + 3x4 = 0

-x2 + 20x3 -7x4 = 0         note: x3 and x4 are free variables

we can take x3 = 0 and x4 = 1 , hence ; x2 = -7

∴ x1 - 28 + 3 = 0 = x1 = 25

W2 = ( x1 ,x2, x3, x4 ) = ( 25, -7 , 0, 1 )

now lets take x3 = 1  and x4 = 0   hence x2 = 20 , x1 = -75

∴ W1 =  ( x1 , x2 , x3, x4 ) = ( -75, 20, 1 , 0 )

one set of data has more variation than the other. hope this !

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: