The length of a rectangle is 8 feet longer than it is wideIf each side is increased 8 feet, then the area is multiplied by 2. What was the size of the original rectangle?

W = 16

L = 24

Step-by-step explanation:

Let's write down the information we have first

"The length of a rectangle is 8 feet longer than it is wide"

L = W + 8

"If each side is increased 8 feet, then the area is multiplied by 2."

(L + 8)(W + 8) = 2LW

Now we can solve for W first, then L

(W + 16)(W + 8) = 2W(W + 8)

W² + 24W + 128 = 2W² + 16W

0 = W²- 8W - 128

0 = (W - 16)(W + 8)

W = 16

L = 24

(This part above is solved like quadratics)

if x = 1, then the answer is 3.5

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