A standard die is rolled. Find the probability that the number rolled is greater than 5. Express your answer as a fraction in lowest terms or a decimal number rounded to three decimal places, if necessary.

1/6

Step-by-step explanation:

Hi!

A standard die has 6 faces including the numbers 1, 2, 3, 4, 5, 6

If we are trying to find the probability that the number rolled is greater than 5, we have to first find how many number are greater than 5. We can see that 6 is the only number greater.

Now we have to find the total amount of possiblities. There are 6 numbers so the total possiblities is 6.

Now we divide the working numbers over the total.

1/6 is the probability that it will roll a number greater than 5.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

mark branliest

step-by-step explanation:

.6 is 1/2 of 12

the answer is actually d. i just took the test