Mathematics, 10.12.2020 03:40 lbell4776
Consider the function f (x) = StartLayout Enlarged left-brace first row negative 4 x squared, x less-than-or-equal-to negative 1 second row negative 3 Superscript negative x Baseline minus 1, x greater-than negative 1 EndLayout.
Which statement explains the continuity of the function at x = โ1?
Because Limit as x approaches negative 1 f(x) = 4 and f(โ1) = 4, it follows that Limit as x approaches negative 1 f(x) = f(โ1). Therefore, the function is continuous at x = โ1.
Because Limit as x approaches negative 1 f(x) = โ4 and f(โ1) = โ4, it follows that Limit as x approaches negative 1 f(x)= f(โ1). Therefore, the function is continuous at x = โ1.
Because Limit as x approaches negative 1 f(x) = 4 and f(โ1) = โ4, it follows that Limit as x approaches negative 1 f(x) โ f(โ1). Therefore, the function is not continuous at x = โ1.
Because Limit as x approaches negative 1 f(x) = โ4 and f(โ1) = 4, it follows that Limit as x approaches negative 1 f(x) โ f(โ1). Therefore, the function is not continuous at x = โ1.
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Consider the function f (x) = StartLayout Enlarged left-brace first row negative 4 x squared, x less...
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