4) Find the slope and y-intercept for each linear equation and determine if the graphs of the pair are parallel, perpendicular, concurrent (but not perpendicular), or
coincident.
slope =
y-intercept =
x = 3y + 9
-3
y-intercept =
&
slope =
= – y +2 1/2
3
The lines are
5) Find the slope and y-intercept for each linear equation and determine if the graphs
of the pair are parallel, perpendicular, concurrent (but not perpendicular), or
coincident

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation: