A juggler tosses a ball into the air. The balls height, h, and the t seconds can be represented by the equation h(t)=16t^2+40t+4. Suppose the juggler missed and the ball hit the ground. Find the maximum height of the ball and the time it took the ball to reach the ground. Round all answers to the nearest hundredth

h= -20

t = -0.104 and -2.39s

Step-by-step explanation:

A juggler tosses a ball into the air. The balls height, h, and the t seconds can be represented by the equation h(t)=16t^2+40t+4. Suppose the juggler missed and the ball hit the ground. Find the maximum height of the ball and the time it took the ball to reach the ground. Round all answers to the nearest hundredth

The velocity of the body at its maximum height is zero

V= dh/dt

dh/dt = 32t + 40

0 = 32t+40

-32t = 40

t = 40/-32

t = -1.25s

Substitute t = -1.25 into the expression

h(t)=16t^2+40t+4.

h(-1.25)=16(-1.25)^2+40(-1.25)t+4.

h = 16(1.5625)-50+5

h = 25-45

h =-20

Hence the maximums height is -20m

The ball will reach the ground at h = 0

Substitute

h(t)=16t^2+40t+4.

0 = 16t^2+40t+4

Divide through by 4

0 = 4t²+10t+1

Factorize

-10±√10²-4(4)/2(4)

t = -10±√100-16/8

t = -10±√84/8

t =-10+9.17/8

t = -0.83/8 and -19.17/8

t = -0.104 and -2.39s

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

i dont know

step-by-step explanation: