In 2010 an item cost $200. The price increase by 1.5% each year. How much wil it cost in 2030? Round
your
answer to the nearest cent.

Step-by-step explanation:

Let P be price after t year . From the formula of compounding

P = 9 (1.015)^t

Taking log to the base e on both sides

ln P = ln 9 + t ln 1.015

= (2.197 + .0149t )

P = e^{(2.197+.0149t)}

x + 4/7

step-by-step explanation:

use cymath

choose (5, 1.5) and (-1.5,-3.5)

step-by-step explanation:

5 - 1.5 =3.5

-1.5 - (-3.5) = 2

3.5 + 2 =5.5

hope this !