Part 1 Solve the following equation
3(2y + 4) = -2y + 20
(show steps)
part2
what is the value of y?

1

Step-by-step explanation:

3(2y+4)=-2y+20 distribute

6y+12=-2y+20 isolate variable

8y+12=20 subtract number

8y=8

y=1

Hope this helps plz hit the crown :D

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: 177/8

step-by-step explanation: