Given f(x) = 6(1 − x), what is the value of f(−7)?

:⟶f(x)=6(1−x)

{:}\longrightarrow\tt f (-7)=6 (1-(-7)):⟶f(−7)=6(1−(−7))

{:}\longrightarrow\tt f (-7)=6 (1+7):⟶f(−7)=6(1+7)

{:}\longrightarrow\tt f (-7)=6(8):⟶f(−7)=6(8)

{:}\longrightarrow\tt f (-7)=48:⟶f(−7)=48

\therefore\sf f (-7)=48∴f(−7)=48

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6   llegue

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: