What is the solution to the following system x+y+z=6 and x-y+z=8 and x+y-z=0

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Step-by-step explanation:

(eq-1) → x + y + z = 6

(eq-2) → x - y + z = 8

(eq-3) → x + y - z = 0

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Eliminate eq-1 and eq-3

x + y - z = 0    

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Eliminate eq-1 and qe-2

x - y + z = 8    

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Substitute the value of z and y to on of equations

The solution for the following system is:

Step-by-step explanation:

We need to find the solution to the following system.

Let:

Adding eq(1) and eq(2)

Adding eq(2) and eq(3)

We get value of x=4

Now, putting value of x in eq(4) to find value of z

We get value of z=3

Now, putting value of x and z in eq(1) to find value of y

So, value of y=-1

The solution for the following system is:

  or  

step-by-step explanation:

if the four friends split the cost, p, of the pizza evenly, then each friend pays one-fourth of the cost of the pizza.

the expression is   or  

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step-by-step explanation: