A farmer needs to fence a rectangular plot of land with the area of 3000 square yards. He considers several possible length of the plot: 50 yards, 40 yards, 48 yards, and 36 yards. What will be the width of the plot in each case? Do the length and the width of the rectangular plot vary directly or inversely when the same area is needed? Explain why. A

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

-81 -56 -27 0 81

step-by-step explanation:

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.