Gabriel detecto una gotera en el lavabo de su casa si 20 gotas equivalen a 1ml en cuanto tiempo se vaciara el tinaco de 200 litros Y necesito la expresión algebraica porfa me urge

Respuesta: 4000000 gotas

Explicación paso a paso:

Capacidad del tanque de agua = 200 litros

Si 20 gotas de agua de una fuga = 1 ml

¿Cuánto tiempo se tarda en vaciar el depósito de 200 L?

Recordar :

1L = 1000 mL

Por lo tanto,

200L = 200 * 1000 = 200000 ml

Por lo tanto,

Si ;

20 gotas = 1 mL

x gotas = 200000 mL

x gotas = 20 * 200000

x = 4000000 gotas

Por lo tanto, se necesitarán 4 millones de gotas para que todo el tanque de 200 L esté vacío.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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