A skyscraper is 396 meters tall. At a certain time of the day, it's casts a shadow that is 332 meters long. At what angle is the sun above the horizon at that time?

56.96°

Step-by-step explanation:

The set up will give a right angles triangle where;

The height of the sky scraper = hypotenuse side = 396m

The length of the shadow will be the opposite = 332m

According to the SOH trig identity

sin theta = opp/hyp

sin theta = 332/396

sin theta = 0.8383

theta = arcsin 0.8383

theta = 56.96°

Hence the sun is at 56.96° above the horizon

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336