The 8th grade students at two middle schools are raising money by washing cars. Eastern School has already raised $625 and charges $4.50 per car. West School
charges $6.00 per car and has already raised $475. Which of the following equations
can be used to find c, the numbeſ of cars each school needs to wash so that the total
amount raised is the same for both schools?
A. 6250 +4.5 = 4750 6
B. 4.50 625 60 475
C. 625c 6 = 4750 4.5
D. 4.50 475 60 625

16

step-by-step explanation:

2 x 40 = 80

80/5

= 16

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200