As part of the underwriting process for insurance, each prospective policyholder is tested for high blood pressure. Let X represent the number of tests completed when the first person with high blood pressure is found. The expected value of X is 12.5. Calculate the probability that the sixth person tested is the first one with high blood pressure.

0.053

Step-by-step explanation:

This is a geometric distribution problem.

I'm geometric distribution problem,

E(X) = 1/p

Where;

E(X) is expected value and p is probability of success

Thus;

1/p = 12.5

p = 1/12.5

p = 0.08

Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;

P(X = k) = qⁿ•p

q = 1 - p

q = 1 - 0.08

q = 0.92

Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;

P(X > 5) = (0.92^(5)) × 0.08

P(X > 5) = 0.053

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

over the argument its not good to fight.