The weekly volume (in liters) of milk produced in a farm is given by v(x)=x3+21x2-1480x, where x is the number of cows. Find the number of cows that corresponds to a total production of 1500 liters of milk in a week

30 cows

Step-by-step explanation:

The given parameters are;

v(x) = x³ + 21·x² - 1480·x

Where x = The number of cows

V(x) = The weekly volume (in liters) of milk produced

The number of cows that corresponds to a total production of 1500 liters of milk in a week is given as follows;

1,500 = x³ + 21·x² - 1480·x

x³ + 21·x² - 1480·x = 1,500

x³ + 21·x² - 1480·x - 1,500 = 0

x³ + 21·x² - 1480·x - 1,500 = 0

We observe that x = -1 is a solution of the above equation, as follows;

(-1)³ + 21·(-1)² - 1480·(-1) - 1,500 = 0

Therefore, (x + 1) is a factor of x³ + 21·x² - 1480·x - 1,500, which by long division gives;

  x² + 20·x - 1500

(x³ + 21·x² - 1480·x - 1,500)/(x + 1)

        x³ + x²

           20·x² - 1480·x - 1500

           20·x² + 20·x        

                       -1500·x - 1500

                      -1500·x - 1500

Therefore, the other factors is x² + 20·x - 1500, which gives;;

x² + 20·x - 1500 = (x - 30) × (x + 50)

Therefore;

x³ + 21·x² - 1480·x - 1,500 = 0

Which gives;

(x - 30) × (x + 50) × (x + 1) = 0

The solutions are x = 30, or x = -50, or x = -1

Therefore, the only possible solution is the number of cows = x = 30 cows.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

step-by-step explanation:

bob the banana