A company set aside a certain amount of money in the year 2000. The company spent exactly exactly $29,000 from that fund each year on perks for its employees. In 2002, there was still $763,000 left in the fund.
Let x be the number of years since 2000, and let y be the amount of money left in the fund that year. Use a
linear equation to model the amount of money left in the fund after so many years.
a. The linear model's slope-intercept equation is y=-29000x + 821000/-
left in the fund.
b. In the year 2010, there was
the fund will be empty.
c. In the year

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen