Can Someone answer this pleaseee Matthew has a jar of 368 nickels and dimes he has been collecting. The total value of the coins is $28.40.Which system of linear equations and solution can be used to represent the number of nickels and dimes Matthew has in his collection?

A. n + d = 368 0.05n + 0.1d=28.4 168 nickels and 200 dimes
B. n + d = 368 0.01n + 0.05d=28.4 200 nickels and 168 dimes
C. n + d = 368 0.05n + 0.1d=28.4 200 nickels and 168 dimes
D. n + d = 368 0.1n + 0.05d=28.4 168 nickels and 200 dimes

from the given, you already have the number of nickels which is 368 so the missing is how many dimes are in the jar that has $28.40...

so what I will do here, if it was me,

(368 x .05) + (?? x .10) = $28.40

being said...

.05 is the value of a nickel

.10 is the value of a dime

368 x .05 is $18.40

thats how much is the nickels cost

then subtract it to the total money Matthew have

$28.40 - $18.40 = $10

meaning there is $10 amount of dimes in the jar...

$10 / .10 = 100

so yea...

there is 368 nickels and 100 dimes combined in Matthew's jar to total of $28.40

Step-by-step explanation:

i hope this helps