Sterling has prepared the following two-column proof below. He is given that ∠OLN ≅ ∠LNO and he is trying to prove that OL ≅ ON. Triangle OLN, where angle OLN is congruent to angle LNO
Step Statement Reason
1 ∠OLN ≅ ∠LNO Given
2 Draw OE as a perpendicular bisector to LN by Construction
3 m∠LEO = 90° Definition of a Perpendicular Bisector
4 m∠NEO = 90° Definition of a Perpendicular Bisector
5 LE ≅ EN Definition of a Perpendicular Bisector
6 ΔOLE ≅ ΔONE Hypotenuse-Leg (HL) Postulate
7 ∠LEO ≅ ∠NEO Transitive Property of Equality
8 OL ≅ ON CPCTC
Sterling made two errors in the proof. Identify and correct the errors

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

nlgqer

step-by-step

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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