Find three consecutive odd integers whose sum is-213.

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

Step-by-step explanation:

let the first odd number be x

second odd number be x + 2

third odd number be x + 4

Now, three consecutive odd integers whose sum is - 213.

i.e.,

(x) + (x + 2) + (x + 4) = - 213

Then,

(x) + (x + 2) + (x + 4) = - 213

x + x + 2 + x + 4 = - 213

3x + 6 = - 213

3x = - 213 - 6

3x = - 219

x = - 219/3

x = - 73

Thus, The value of x is - 73

Here,

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

So

(x) + (x + 2) + (x + 4) = - 213

(- 73) + (- 73 + 2) + (- 73 + 4) = - 213

(- 73) + (- 71) + (- 69) = - 213

- 73 - 71 - 69 = - 213

- 213 = - 213

Hence, L.H.S = R.H.S

-TheUnknownScientist

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true