Plane A is descending toward the local airport at a rate of 2,500 feet/minute. It is currently at an altitude of 12,000 feet. Plane B is ascending from the same airport at a rate of 4,000 feet/minute. It is currently at an altitude of 1,000 feet. This system of equations models this real-world situation, where x represents the time in minutes and y represents the altitude in thousands of feet: y = 12 − 2.5x y = 1 + 4x Graph the lines of the two equations, and mark the point of intersection for the two lines. In approximately how many minutes will the two planes be at the same altitude? At what altitude will they be?

The point of intersection is located at approximately (1.75,7.75), which means both planes will be at an altitude of about 7,750 feet after approximately 1.75 minutes, or 1 minute, 45 seconds.

This is what the graph looks like:

Step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;