What is the equation of the line that passes through the point (-3, 2) and
has a slope of –2/3

y = -2/3 (x+3) + 2

Step-by-step explanation:

use the point-slope form equation: y - y1 = m (x - x1)

plug in the point (-3,2) and slope -2/3 into the equation:

y - 2 = -2/3 [x - (-3)]

you can simplify it:

y - 2 = -2/3 (x+3)

and you can also put it in terms of y:

y = -2/3 (x+3) + 2

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: