Classify each system of equations as having a single solution, no solution, or infinite solutions. y = 5 − 2x 4x + 2y = 10 x = 26 − 3y 2x + 6y = 22 5x + 4y = 6 10x − 2y = 7 x + 2y = 3 4x + 8y = 15 3x + 4y = 17 -6x = 10y − 39 x + 5y = 24 5x = 12 − y

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

idk

step-by-step explanation: