Eliminate the parameter “t” for the parametric equations, where 0 < t < 5. x = √5t

y = 2t — 2

Answers:

A) y = 2/5x^2 — 2
B) y = 5/2X^2 — 5
C) y = 2√5x — 2
D) y = 2/5x^2 — 2

A) y = 2/5x^2 — 2

Step-by-step explanation:

We are given the parametric equation:

To express y in terms of x, we solve for t in the first equation and substitute in the second equation.

Squaring:

Solving for t:

Substituting in the second parametric equation:

Correct choice: A) y = 2/5x^2 — 2

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734