Find the value of n that makes ΔDEF ∼ΔXYZ when DE = 4, EF = 5, XY = 4(n+1), YZ = 7n - 1, and ∠E ≅∠Y. n =

3

Step-by-step explanation:

It's given that ΔDEF ∼ΔXYZ . So the corresponding sides of both triangles will be proportional to each other.

DE = 4 ; XY = 4(n + 1) ; EF = 5 ; YZ = 7n - 1

Putting all these values gives ,

its d but looking at that hurts my eyes frfr

step-by-step explanation:

three-fourths of an hour

36÷48=0.75

0.75=