Below is the graph of a trigonometric function. It has a minimum point at \left(1,1.5\right)(1,1.5)left parenthesis, 1, comma, 1, point, 5, right parenthesis and an amplitude of 1.51.51, point, 5.

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

answer: b.36 feet

step-by-step explanation: