For second answer how do you get it plz urgent plz

Step-by-step explanation:

Complete question is attached.

a) ED = 6.5 cm

b) BE = 14.4 cm

Step-by-step explanation:

From the triangle, we are given the following dimensions:

AB = 20 cm

BC = 5 cm

CD = 18 cm

AE = 26 cm

We are asked to find length of sides ED and BE.

a) Find length of ED.

From the triangle Let's use the equation:

\frac{AB}{BC} = \frac{AE}{ED}BCAB=EDAE

Cross multiplying, we have:

AB * ED = AE * BC

From this equation, let's make ED subject of the formula.

ED = \frac{AE * BC}{AB}ED=ABAE∗BC

Let's substitute figures,

ED = \frac{26 * 5}{20}ED=2026∗5

ED = \frac{130}{20} = 6.5ED=20130=6.5

Therefore, length of ED is 6.5 cm.

b) To find length of BE, let's use the equation:

\frac{AB}{AC} = \frac{BE}{CD}ACAB=CDBE

Cross multiplying, we have:

AB * CD = AC * BE

Let's make BE subject of the formula,

BE = \frac{AB * CD}{AC}BE=ACAB∗CD

From the triangle, length AC = AB + BC.

AC = 20 + 5 = 25

Substituting figures, we have:

BE = \frac{20 * 18}{25}BE=2520∗18

BE = \frac{360}{25} = 14.4BE=25360=14.4

Therefore, length Of BE is 14.4cm

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b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.