Sushil, Alex and Peter share some sweets in the ratio 6:5:1. Sushil gets 60 more sweets than Peter. How many sweets are there altogether?

There are 144 sweets altogether.

Step-by-step explanation:

Let us call:

S = Number of sweets Sushil's sweets

A = Number of sweets Alex' sweets

P = Number of sweets Peter's sweets

The ratio between them is S:A:P = 6:5:1. It must be separated as:

Or, equivalently:

5S = 6A        [1]

Also:

Or, equivalently:

A = 5P          [2]

We also know Sushil gets 60 more sweets than Peter:

S = P + 60     [3]

Solving for P:

P = S - 60     [4]

Substituting in [2]:

A = 5(S - 60) = 5S - 300     [5]

Substituting in [1]

5S = 6(5S - 300)

Operating:

5S = 30S - 1800

Rearranging:

25S = 1800

Dividing by 25:

S = 1800/25=72

S = 72

Substituting in [5]:

A = 5(72) - 300

A = 60

Substituting in [4]:

P = 72 - 60

P = 12

In total there are 72 + 60 + 12 = 144.

There are 144 sweets altogether.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]