A food scientist uses a mixture of the gases helium and argon to preserve packaged food. The amount of each gas the scientist uses for the mixture is modeled by the equation 5.6H + 0.56A = 22.4, where H and A
are the masses, in grams, of helium and argon, respectively. If the scientist uses 10 grams of argon, how
many grams of helium are used?

9514 1404 393

  3 grams of helium are used

Step-by-step explanation:

Solving the given equation for H, we have ...

  5.6H +0.56A = 22.4

  5.6H = 22.4 -0.56A

  H = (22.4 -0.56A)/5.6

  H = 4 -0.1A

Using A=10, we find ...

  H = 4 -0.1·10 = 3

3 grams of helium are used.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the first option is the answer.