Find the equation of the line through (-4,6) that is parallel to the line y=-5x+2

The equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:

Step-by-step explanation:

We know that the slope-intercept form is

Where m is the slope and b is the y-intercept

Given the equation

comparing with the slope-intercept form

slope = m = -5

y-intercept = b = 2

We know that the parallel lines have the same slopes.

so , the slope of the parallel line will be: -5

Thus, the equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²